0=9x^2-98x+198

Solution for 0=9x^2-98x+198 equation:

0=9x^2-98x+198

We move all terms to the left:

0-(9x^2-98x+198)=0

We add all the numbers together, and all the variables

-(9x^2-98x+198)=0

We get rid of parentheses

-9x^2+98x-198=0

a = -9; b = 98; c = -198;
Δ = b2-4ac
Δ = 982-4·(-9)·(-198)
Δ = 2476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2476}=\sqrt{4*619}=\sqrt{4}*\sqrt{619}=2\sqrt{619}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-2\sqrt{619}}{2*-9}=\frac{-98-2\sqrt{619}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+2\sqrt{619}}{2*-9}=\frac{-98+2\sqrt{619}}{-18}
$